Question

In the given quadrilateral ABCD, the side BD=15cm and the heights of the triangles ABD and BCD are 5cm and 7cm respectively.Find the area of the quadrilateral ABCD.
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Answer 1

Answer:

Diagonal = BD = 15 cm

Heights, h1=5 cm & h2=7 cm

Sum of the heights of the triangles = h1 + h2 = 5 + 7 = 12 cm

Thus, area of quadrilateral ABCD =

=12×diagonal×(Sum of height of two triangle)

= (15 * 12)/2 = 90 Cm2

Step-by-step explanation:

hope you help

Answer 2

Answer:

90 square cm

Step-by-step explanation:

The height of triangle ABD is 5 cm

The base of ABD is 15

area = 0.5 x 15 x 5 = 37.5

The height of triangle BCD is 7 cm

The base of bcd is 15 cm

area = 0.5 x 15 x 7 = 52.5

the area of the quadrilateral = area of abd + area of bdc

= 37.5 + 52.5

= 90 square cm