Math, asked by rachith95, 1 year ago

- In the given rectangle ABCD, DX = DA.What is the measure of angle XAB ?​

Answers

Answered by Kisutu
5

Step-by-step explanation:

draw a straight line connecting X and line AB. say point K.

so, DA=XK and AK=DX.

AKDX is a square now.

Diagonal AX bisects the square AKDX.

So, Angle XAB = 45 Degrees

Answered by Swarit1234
5

Answer:

Angle XAB=45°

Step-by-step explanation:

∆XAD is an isosceles triangle as DX=DA(angleXAD=angleDXA)

In ∆XAD:

angle XDA+ angle XAD+ angle DXA=180°[Angle Sum Property of a ∆]

90°+ angle XAD+ angle DXA=180°

90°+angle XAD+angle XAD=180°

angle XAD+angle XAD=90°[180°-90°]

2angle XAD=90°

angle XAD=45°

angle DAB=90°

angle XAD+angle XAB=90°

angle XAB=90°-angle XAD

angle XAB=90°-45°

angle XAB=45°

Hope it's what you want

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