Question

In the given relation p is pressure z is distance and theta is temperature find dimensional formula of b p= a/b exp(-az theta)​

Answer 1

Answer:

this solution is similar to correct solution.

Explanation:

Power of exponential is dimesnionless.

αZkθ is dimensionless.

α[L][ML2T−2K−1][K] is dimensionless.

[α]=[MLT−2]

Dimensions of αβ = Dimensions of P

[MLT−2]β=[ML01T−2]

[β]=[L2]