Question

In the given rhombusz if AC = 16cm and BD = 12cm, calculate its area:​

Answer 1

Step-by-step explanation:

$area \: of \: rhombus \: = \: \frac{product \: of \: doagonals}{2}$

$= \frac{ac \times bd}{2}$

$= \frac{16 \times 12}{2} \\ = \frac{192}{2} \\ = 96$

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Answer 2

Answer:

The Area of the Rhombus is 96cm

Step-by-step explanation:

In the given diagram AC and BD are diagonal

To find the area of Rhombus

Diagonals are given:

AC= 16 cm

BD= 12cm

Formula for the diagonal is

$\frac{AC X BD}{2}$

Substitute the values in the given formula

$==>\frac{16 X 12}{2}$

==> 16×12=192

$==> \frac{192}{2}$

$==>96 cm$

The Area of the Rhombus is 96cm