Question

In the given right angled triangle, BC = a , CA=b and AB = c. Then prove that a+b = c+d , where d is the diameter of the circle.

Answer 1

let cd=x=cf(tangents drawn from an external point)

so,bf =a-x=be """"""

ad=b-x=ae """"""

now,

ab = be +ae

c = a-x + b-x

a+b = c +2r

a+b=c+d (since 2 radius = diameter)