Question

in the given right angled triangle, if AB=6,BC=4 and AC=10, find a) sinA= opp/hyp =bc/ac= 4/10
b)cosA= adj/hyp =ab/ac=6/10
c)tanA= opp/adj =bc/ab=4/6
d)cosecA=hyp/opp =ac/bc=10/4
e)secA=hyp/adj =ac/ab=10/6
f)cotA=adj/opp=ab/bc=6/4

Answer 1

Answer:

a) 2/5

b) 3/5

c) 2/3

d) 5/2

e) 5/3

f) 3/2

Step-by-step explanation:

a) sinA=opp/hypo=BC/AC=4/10=2/5

b) cosA=adj/hypo=AB/AC=6/10=3/5

c) tanA=opp/adj=BC/AB=4/6=2/3

d) cosecA=hypo/opp=AC/BC=10/4=5/2

e) secA=hypo/adj=AC/AB=10/6=5/3

f) cotA=adj/hypo=AB/BC=3/2