In the given square,
the length of the
diagonals AC and
BD is (32- a) cm and
(a +
8) cm,
respectively. What is
the area of the
square(in cm)?
Answers
Answered by
6
Answer:
diagonals od square are equal
therefore 32-a=a+8
32-8=a+a
24=2a
a=12
area = a²
=12×12
=144cm²
Answered by
0
Given:
Length of diagonal AC = 32 - a
Length of diagonal BD = a + 8
To Find:
The area of the square
Explanation:
It is given that the diagonals of square are equal therefore
(32-a) = (a+8)
(32-8) = (a + a)
24 = 2a
Hence a = 12
Area for the square = a²
We got the value of the side which is 12
Therefore (12)²
= (12×12)
= 144cm²
Hence area of triangle = 144cm²
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