In the given square, the length of the diagonals AC and BD is (32 - a) cm and (a + 8) cm, respectively. What is the area of the square(in c
m
2
)?
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Step-by-step explanation:
the diagonals of a square are equal
so,
32-a=a+8
2a=32-8
a=24/2
a=12cm
area of sqaure=a^2
=12^2=144cm^2
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