Question

In the given structure of a compound, the correct
various bond moments direction involving atoms
are shown as
(1) Br=N=CH, = SiH, = CH, 20=CH,
(2) Br=N=CH, = SiH, = CH, =0= CH,
(3) Brz N =CH, = SiH= CH, =0=CH,
(4) Br=N 2CH, = SiH, = CH, 202CH,​

Answer 1

Brz N =CH, = SiH= CH, =0=CH is the correct option.

Explanation:

• The bond dipole is the shift of electron cloud to one side of the bond.

• This dipole is formed when a participating atom participates in the bond with higher electronegativity.

• This higher electronegativity leads to more attraction of electron cloud in the bond.

• As far as the elements given in the question are concerned, nitrogen has an electronegativity of 3.04, oxygen has 3.44, silicon 1.96, bromine 2.96 and carbon 2.55.

• So the electronegativity trend is O>N>Br>C>Si.

• This leads to the attraction of electron cloud of silicon by carbon, that by bromine, that by nitrogen and finally by oxygen.

• So this leads to option 3 being the correct option.

For more information about electronegativity,

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