In the given table replace question marks with a digit so that the sum of the numbers of that row
or column is a multiple of number mentioned. Remember no digit should repeat in the same row
or column.
2 5 ? 8 Multiple of 9
4 ? 7 1 Multiple of 10
9 ? 4 ? Multiple of 3
? 4 1 6 Multiple of 2
Multiple of 5 Multiple of 9 Multiple of 3 Multiple of 2
Answers
Answer:
8; 0; 6 and 9; 8
Step-by-step explanation:
Given : sum of the numbers of that row or column is a multiple of number mentioned. Remember no digit should repeat in one row or column.
To Find : Missing Digits
Solution:
2 5 a 8 Multiple of 9
4 b 7 1 Multiple of 10
9 c 4 d Multiple of 3
e 4 1 6 Multiple of 2
Multiple 5 9 3 2
2 + 4 + 9 + e = Multiple of 5
=> 15 + e = Multiple of 5
=> e = 0 , 5
e + 4 + 1 + 6 Multiple of 2
=> e + 11 Multiple of 2
Hence e = 5
2 + 5 + a + 8 = Multiple of 9
=> a = 3
3 + 7 + 4 + 1 = 15 multiple of 3 : column satisfies also
4 + b + 7 + 1 Multiple of 10
=> b = 8
5 + b + c + 4 = Multiple of 9
=> b + c = 9 , b + c = 18 ( 18 not possible as then 9 will repeat )
b = 8
c = 1
9 c 4 d Multiple of 3
=> 9 + 1 + 4 + d Multiple of 3
=> 14 + d Multiple of 3
=> d = 1 , 4 , 7 ,
8 + 1 + d + 6 Multiple of 2
Hence d = 1 , 3 , 5 , 7 , 9
1 and 7 common
1 is already in column
Hence d = 7
2 5 3 8 Multiple of 9
4 8 7 1 Multiple of 10
9 1 4 7 Multiple of 3
5 4 1 6 Multiple of 2
Multiple 5 9 3 2
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