In the given the diameter CD of a circle with center O is perpendicular to the chord AB. If AB = 8 cm and CM = 2 cm, find the radius of the circle.
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14
Answer:
By using Pythagoras Theorem,
r^2 = AB^2 + CM^2
r^2 = 8^2 + 2^2
r^2 = 64 + 4
r^2 = 68
r = √68
r = 2√17 cm.
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Answered by
13
Answer:
5cm
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