Question

in the given the figure ABCD is a rectangle and ABED is a parallelogram. Given AB = 16 cm , AD = 10 cm. Find the area of triangle ABF



PLZZZ HELP ME!!!!


NO SPAM PLZZ​

Answer 1

Answer:

80 sq. cm

Step-by-step explanation:

ABCD is a rectangle (given)

AB = 16cm (given)

AD = 10 cm (given)

We know that,

"Parallelograms on the same base and between same parallels are equal in area."

Rectangle ABCD and parallelogram ABEF lies on same base AB.

So,

Area of Rectangle ABCD = Area of parallelogram ABEF.

Length * Breadth of rectangle = Area of parallelogram.

=> Area of parallelogram ABEF = 10 * 16 = 160 Sq. cm.

If BF is the diagonal, The Parallelogram is made of two triangles ABF and BFE.

Area of triangle ΔABF = 1/2 of the area of parallelogram ABEF = 160/2 = 80 sq. cm

Answer 2

Answer: 16 × 10=area of triangle or something

Step-by-step explanation: A to F is 10.

A to B is 16

The method for finding triangle area is :

base( the bottom of the triangle) × height ( the perpendicular side of the triangle/left side* can sometimes be in the middle*)÷ by 2

OR

1/2 base × height

Hope this helps