Question

in the given trapezium lmnp, lm ll np . if angle n = 100 and angle p =70 then find the measure of angle plm and angle nml
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Answer 1

Answer:

<PLM=110° and <NML=80°

Given:

A trapezium LMNP in which LM||NP.

<MNP=100° and <NPL=70°

To find:

<PLM and <NML

Solution:-

<MNP=100° (Given)

LM||NP

So

<MNP+<NML=180° (co-int-angle)

100°+<LMN=180°

<NML=80°

Similarly

<PLM+<NPL=180° (Reason stated above)

<PLM+70°=180°

<PLM=110°

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<PLM=110° and <NML=80°

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Verifi©ation

70°+100°+80°+110°=360° (sum of angles of trapezium)

360°=360°

L.H.S=R.H.S

Answer 2

Answer:

<plm  = 110

<nml = 80

Step-by-step explanation:

we know that Two angles on the same side are supplementary, that is the sum of the angles of two adjacent sides is equal to 180° in a trapezuim .

=> angle " l " and angle " p " are adjacent to each other .

<lpn + <plm  = 180

70 + <plm = 180

<plm = 180 - 70

<plm = 110

and <mnp + <nml = 180

100 +   <nml = 180

<nml = 180 - 100

<nml = 80