Question

In the given trapezium the diagonal BD, bisects diagonal AC in the ratio 2:1, then

AB is equal to..

A)2 AB B) 2 BC C) 2 CD D) 2 BD​

Answer 1

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

$\huge\underline\mathcal\green{C) 2CD}$

$\huge{\fbox{\fbox{\orange{\mathfrak{Explanation}}}}}$

$<marquee behaviour="slide" direction="up" style ="background:white">$

Given, that the diagonal BD

divides the AC in AO : OC

with 2 : 1

To prove : AB = 2CD

Proof : In 

Δ AOC and Δ DOC

AOB = COD

OBA = ODC (Because DC is

parallel to AB, and DB is

transversal. So, these are

alternates)

Therefore,

Δ AOB is same as Δ COD

(By AA similarity)

Now, AO/OC = AB/DC

(Because in similar triangles

sides are proportional)

➡️ 2/1 = AB/DC

(Given that AO : OC = 2 : 1)

So, AB = 2CD

Hence proved.

Answer 2

Answer:

____________________________________