In the given triangle AB=AS and BP=VS then show that PA=AS
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Since the triangle ABC is an equilateral triangle, each angle =60
o
Clearly, from the figure, ∠BAP>∠ABP since ∠BAP=60
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and ∠ABP is a part of 60
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This means, the sides opposite to the angles will also
have the same relation.
∴BP>PA
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