In the given triangle ABC , AD⊥BC , AB = 13cm , BD = 5cm and DC = 4cm . Find the value of :
a) AD
b) tan x° + cot y°
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Answer:
AD = 12 cm
tan x + cot y = 41/15
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Answer.
a) AD - 12 cm
b) tan x - 1/3
cot y - 12/5
tan x + cot y - 41/15.
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