in the given triangle ABC line PQ is parallel to side BC then angle B = angle P because they are _________.
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In ΔAPQ and ΔABC,
∠ACQ=∠ABC [As PQ || AB, corresponding angles are equal.]
$$\angle{PAQ = \angle{BAC}$$ [Common angle]
Hence, ΔAPQ ~ ΔABC by AA criterion for similarity
So, we have
AP/AB=AQ/AC
AP/9=4.2/6
Thus,
AP=6.3cm
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