in the given triangle ABC prove that,
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Step-by-step explanation:
(b+c)cosA+(c+a)cosB+(a+b)cosc
=b cosA+c cosA+c cosB +a cosB + a cosC + bcosc
= (bcosC+c cosB)+(acosC+c cosA) +
(a cosB + b cos A)
= a + b + c
Answered by
1
Answer:
Step-by-step explanation:
bcosC+c cosB)+(acosC+c cosA) +
(a cosB + b cos A)
a + b + c
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