Question

In the given triangle ABCD, "D" is midpoint on BC . AD is produced to E such that AD = DE. Prove that that ABEC is a parallelogram
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please try to give handwritten answers

Answer 1

Answer:

Solution :-

in the figure

△DCE and BFE

any DEC = any BEF (vertically opp any)

EC=BE (E is the mid point)

∠DCB=∠EBF (alternate angle DC parallel to AF)

So △DCE congruent to △BFE

Therefore DC=BF ...(1)

now CD = AB (ABCD is a parallelogram)

soAF=AB+BF

=AB+DC from (1)

=AB+AB

=2AB

solution

Answered By

toppr

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