Math, asked by rashmichawla2618, 4 months ago

In the given triangle M, N and O are the respective mid points of BC, CA and AB. If AB = 60 cm, BC = 58 cm, AC = 42 cm, then what is the perimeter of quadrilateral AOMN?
plz answer it's urgent

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Answers

Answered by reena3440r
5

Answer:

102 cm

Step-by-step explanation:

AB = 60 cm

AC = 42 cm

so, AN = 30 cm( N is in the mid of AC)

AO = 21 cm ( O is in the mid point of AB)

AN=OM ( opp sides of llgm)

OM=MN (opp sides of llgm )

so perimeter = 30 + 30 + 21 + 21

= 102 cm

I hope it helps you out

Answered by Anonymous
2

Given:

AB=60cm

BC=58cm

AC=42cm

To find:

The perimeter of the quadrilateral AOMN

Solution:

The perimeter of the quadrilateral AOMN is 102 cm.

We can find the perimeter by following the given steps-

We know that the points M, N, and O are the midpoints of BC, AC and AB.

This means that AO=OB, BM=MC, and AN=NC.

Since OM passes through the midpoints of AB and BC, OM is parallel to AC and equal to half of it. (Midpoint theorem)

OM=1/2 of AC

Similarly, MN is parallel to AB and equal to half of it.

MN=1/2 of AB

Now, in quadrilateral AOMN, the perimeter is the sum of all its sides.

The sides of AOMN are AO, OM, MN, and AN.

The perimeter of AOMN=AO+OM+MN+AN

AO=MN=1/2 of AB=1/2 of 60=30cm

OM=AN=1/2 of AC=1/2 of 42=21cm

On putting the values, we get

Perimeter of AOMN=30+21+30+21

=42+60

=102cm

Therefore, the perimeter of the quadrilateral AOMN is 102 cm.

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