In the given triangle PQR, AB || QR, QP || CB and AR intersects CB at O. P B 3c 6c С 4c R Q Using the given diagram answer the following question: The triangle similar to AARQ is (b) AARP (C) AOBR (a) AORC (d) AQRP (1) APQR ~ABCR by axiom (b)AAA (a) SAS (c) SSS (d) AAS If QC =6 cm, CR = 4 cm, BR = 3 cm. The length of RP is (b) 8cm (c) 7.5cm (a) 4.5 cm (d) 5cm (iv) The ratio PQ: BC is (a) 2:3 (b) 3:2 (c) 5:2 (d) 2:5
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∆ARQ~∆ORC
∆PQR~∆BCR by AAA axiom
7.5 cm
5:2
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10
(1) In ∆ARQ and ∆ORC we have ,
→ QA || CO { given that, QP || CB . }
therefore,
→ ∠QAR = ∠COR { Corresponding angles. }
→ ∠ARQ = ∠ORC { Common angles. }
therefore,
→ ∆ARQ ~ ∆ORC { By AA similarity. }
therefore, (a) ∆ORC is correct answer .
(2)
since,
→ QP || CB,
In ∆PQR and ∆BCR we have,
→ ∠PQR = ∠BCR { Corresponding angles. }
→ ∠PRQ = ∠BRC { Common angles. }
→ ∠QPR = ∠CBR { Corresponding angles. }
So,
→ ∆PQR ~ ∆BCR { By AAA similarity. }
therefore, (b) AAA is correct answer .
(3)
since,
→ ∆PQR ~ ∆BCR
→ QR/CR = RP/RB
→ (6+4)/4 = RP/3
→ 10/4 = RP/3
→ RP = 30/4
→ RP = 7.5 cm (C)
(4)
similarly,
→ PQ/BC = QR/CR
→ PQ/BC = 10/4
→ PQ/BC = 5/2
→ PQ : BC = 5 : 2 (c)
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