Math, asked by alpanas66, 10 days ago

In the given triangle PQR, AB || QR, QP || CB and AR intersects CB at O. Using the given diagram answer the following question: (i) The triangle similar to ΔARQ is (a) ΔORC (b) ΔARP (c) ΔOBR (d) ΔQRP (ii) ΔPQR ~ΔBCR by axiom (a) SAS (b)AAA (c) SSS (d) AAS (iii) If QC =6 cm, CR = 4 cm, BR = 3 cm. The length of RP is (a) 4.5 cm (b) 8cm (c) 7.5cm (d) 5cm (iv) The ratio PQ: BC is (a) 2 : 3 (b) 3 : 2 (c) 5 : 2 (d) 2 : 5​

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Answers

Answered by Briliany22
26

Answer:

(i) a) ΔORC

(ii) b) AAA

(iii) c) 7.5 cm

iv)  c) 5:2

Step-by Step explanation

iii) Since ΔPQR ~ΔBCR

    PQ/BC  =  QR/CR   =  PR/BR

    QR=QC+CR

    QR=6+4

    QR=10cm

     Therefore,

     QR/CR  =  PR/BR

     10/4       =   PR/3

      5/2  *3  = PR

      PR= 15/2 = 7.5 cm

iv)  PQ/BC  =  QR/CR  

     PQ/BC  =   10/4

     PQ/BC  =    5/2

     PQ:BC  =     5:2

Answered by RvChaudharY50
16

Given :- In the given triangle PQR, AB || QR, QP || CB and AR intersects CB at O.

Solution :-

(i)

In ∆ARQ and ∆ORC we have,

→ AQ || OC { Since we have given that, QP || CB }

So,

→ ∠QAR = ∠COR { Corresponding angles }

→ ∠ARQ = ∠ORC { Common angles }

→ ∠AQR = ∠OCR { Corresponding angles }

then,

→ ∆ARQ ~ ∆ORC { By AAA similarity }

Therefore, Option (A) ∆ORC is correct answer .

(ii)

In ∆PQR and ∆BCR we have,

→ QP || CB { given }

So,

→ ∠QPR = ∠CBR { Corresponding angles }

→ ∠PRQ = ∠BRC { Common angles }

→ ∠PQR = ∠BCR { Corresponding angles }

then,

→ ∆PQR ~ ∆BCR { By AAA similarity }

Therefore, Option (b) AAA is correct answer .

(iii)

from (ii) we get,

→ ∆PQR ~ ∆BCR

So,

→ PQ/BC = QR/CR = PR/BR { when two ∆'s are similar their corresponding sides are in same ratio.}

→ QR/CR = PR/BR

→ (QC + CR)/CR = (PB + BR)/BR ------------ Equation (1)

given that, QC =6 cm, CR = 4 cm, BR = 3 cm.

Let PB = x cm . Putting all these values in Eqn.(1) now,

→ (6 + 4)/4 = (x + 3)/3

→ 10/4 = (x + 3)/3

→ 5/2 = (x + 3)/3

→ 15 = 2(x + 3)

→ 15 = 2x + 6

→ 15 - 6 = 2x

→ 2x = 9

→ x = 4.5

therefore,

→ RP = RB + BP

→ PR = BR + PB

→ PR = 3 + 4.5

→ PR = 7.5 cm .

Therefore, Option (c) 7.5 cm is correct answer .

(iv)

from (ii) again,

→ ∆PQR ~ ∆BCR

So,

→ PQ/BC = QR/CR = PR/BR { when two ∆'s are similar their corresponding sides are in same ratio.}

→ PQ/BC = PR/BR

→ PQ/BC = 7.5/3

→ PQ/BC = 75/30

→ PQ/BC = 5/2

→ PQ : BC = 5 : 2

Therefore, Option (c) 5 : 2 is correct answer .

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