In the given triangle pqr, right angled at q, qr=9cm and pr-pq=1cm,determine sin r + cos r
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Answered by
210
pr-pq=1
PR=1+pq
qr=9
by Pythagoras theorem,
pq²+qr²=pr²
pq²+81=(1+pq)²=1+pq²+2pq
80=2pq
pq=40
PR=41
sin r+ cos r
pq/PR+qr/PR
40/41+9/41
49/41
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PR=1+pq
qr=9
by Pythagoras theorem,
pq²+qr²=pr²
pq²+81=(1+pq)²=1+pq²+2pq
80=2pq
pq=40
PR=41
sin r+ cos r
pq/PR+qr/PR
40/41+9/41
49/41
plzz mark me as brainlist
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80
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