In the given tzaiangleABC angle B =90° AC=5cm and Bc =4cm Find the primeter
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in traingle ABC<ABC = 90°
AC=5cm. BC= 4 cm
by Pythagoras theorem
Ac^2= AB^+BC^2
(5)^2= AB^2+(4)^2
25= AB^2+16
AB^2=25-16=9
AB= 3 cm
perimeter of traingle ABC =AB+BC+ AC
(3+4+5) cm
12 cm
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