in the givenfig why will the blub x brightness increase if switch s is closed
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See what happens after the switch is closed:
- Current flows from the postive terminal to the negative terminal(since it's opposite to the flow of electrons).
- Current goes towards bulb x and then distributes equally among bulb y and z.
- Current continues to flow in the same directed path till the switch is again opened.
Now herein, since bulb x gains the exact current flowing in the whole circuit, say ß Ampere, because it is connected in series with the circuit. The other two bulbs gain a comparitively lesser current due to its equal distribution among the two bulbs (since they are in a parallel combination).
Thus, bulb x glows brighter than the other two bulbs.
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