Question

In the gives figure ABCD is a parallelogram in which AP produced to E so that BE = AB prove that ED bisect BC ​

Answer 1

Answer:

REF.Image.

As, AB=BE

B is mid point of AE

Consider △EAD

From midpoint Theorem

BM=21AD (AsAD∥BM) & B is mid point of AE

⇒=21BC (As AD = BC for parallelogram)

⇒ M is midpoint of BC 

Hence ED bisects BC

Step-by-step explanation:

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