Question

in the graph of linear equation 2x+5y=41,there is a point such that it's ordinate is 3 loss than it's abscissa.find the co ordinates of the point​

Answer 1

Answer:

ANSWER

Let the abscissa be a

Then ordinate =

2a

3

New coordinates of point is (a,

2a

3

)

Given that is a point on line 2x+5y=19

now

2(a)+5(

2a

3

)=19

2a+

2

15a

=19

4a+15a=38

19a=38

a=2

∴ abscissa =2

ordinate =

2

3(2)

=3

∴ the required point(2,3)