Math, asked by prashant2821, 11 months ago

In the group {1,3,7,9} under *10,(3*10 7^-1)-1 =

Answers

Answered by genius123444
1

5×-1=-5

Step-by-step explanation:

The answer is -5

Answered by MaheswariS
3

Answer:

\bf\,(3\,*_{10}\,7^{-1})^{-1}=9

Step-by-step explanation:

In the group {1,3,7,9}

3\,*_{10}\,7=1

\textbf{Inverse of 3 is 7}

\implies\,3^{-1}=7

\text{Now,}

(3\,*_{10}\,7^{-1})^{-1}

\text{Using,the property}

\boxed{\bf\,(a*b)^{-1}=b^{-1}*a^{-1}}

=(7^{-1})^{-1}\,*_{10}\,3^{-1}

\text{Using,the property}

\boxed{\bf\,(a^{-1})^{-1}=a}

=7\,*_{10}\,3^{-1}

=7\,*_{10}\,7

=9

\implies\,\boxed{(3\,*_{10}\,7^{-1})^{-1}=9}

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