Question

In the Haber process of synthesis of ammonia 28 g of N2 is mixed with 10 g of hydrogen molecules. Maximum number of moles of ammonia produced in the reaction is

Answer 1

Answer:

ANSWER

N2+3H2→2NH3

Here.

28 g N2 reacts with 6 g of H2

So,

50 g of N2 react with 286×50g−H2=10.7g but we have only 10g so H2 is limiting reagent..

6 g H2 gives 34g NH3

10g H2 will give 634×10=56.67g−NH3

So number of moles of NH3 formed is,

=Molar−massGiven−mass=1756.67=3.33−moles

Answer 2

Answer:

2 moles

Explanation:

It's obvious from the balanced chemical equation. You don't need to do any sort of calculation.