Question

In the hardware store there are five skeins of copper wire 120, 108, 84, 72, 60 m long. You have to divide them equally.
What will be the maximum length of each part?

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Answer 1

☆ Solution

Radius of the steel cable, r=1.5   cm = 0.015  m

Maximum allowable stress = 108 N/m2

Maximum stress =Areaofcross−sectionMaximumforce

Maximum force = Maximum stress × Area of cross-section

                           = 108×π×(0.015)2

                           = 7.065×104 N

Hence, the cable can support the maximum .

Answer 2

Answer:

Radius of the steel cable, r=1.5 cm = 0.015 m

Maximum allowable stress = 10

8

N/m

2

Maximum stress =

Areaofcross−section

Maximumforce

Maximum force = Maximum stress × Area of cross-section

= 10

8

×π×(0.015)

2

= 7.065×10

4

N

Hence, the cable can support the maximum load of 7.065×10

4

N.