Question

In the hare-tortoise race,the hare ran for 2 min. at a speed of 7.5km/h,slept for 56 min. and again ran for 2 min. at a speed of 7.5km/h. Find the average speed of the hare in race

Answer 1

D1 = 7.5×2/60= 0.25km

D2= 7.5×2/60= 0.25km

Total Distance= 0.25+0.25=0.50km

Total time taken = 2+2+56=60min= 1 HR

Average speed =total distance/ total time
Average speed= 0.50/1= 0.50 km/hr

Answer 2

ANSWER :-

$\frac{0.50km}{1hr}$

HEADING:-

Distance traveled at first 2 min = 7.5km/hr × 2/60 hr

$7.5 \frac{km}{hr} \: \times \frac{2}{60} hr$

$= 0.25km$

Distance traveled at second 2 min = 7.5 km/hr × 2/60 hr

$7.5 \frac{km}{hr} \times \frac{2}{60} hr$

$= 0.25km$

$total \: distance = 0.50km$

$time \: taken = (2 + 2 + 56)min$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1hr$

$average \: speed = \frac{distance \: travelled}{time \: taken}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{0.50km}{1hr}$

HOPE IT HELPS YOU!