Question

In the he given figure, the resistors
(i)6 Ω, 3 Ω and 9 Ω are in series
(ii)9 Ω and 6 Ω are in parallel and the combination is in series with 3 Ω
(iii)3 Ω, 6 Ω and 9 Ω are in parallel
(iv)3 Ω and 6 Ω are in parallel and the combination is in series with 9 Ω.​

Answer 1

1) Rs = r1+r2+r3

= 6+3+9=18ohm

2) 1/Rp= 1/Rp+1/Rp

= 1/9+1/6

= 2+3/18

1/Rp= 5/18

Rp=18/5

total resistance= Rp+Rs

= 18/5+3/1

= 18+15/5 = 33/5 ohm

3) 1/Rp= 1/3+1/6+1/9

= 6+3+2/18

1/Rp = 11/18

Rp= 18/11 ohm

4) 1/Rp= 1/3+1/6

= 2+1/6

1/Rp =3/6

Rp=6/3=2ohm

total resistance= Rp+Rs

= 2+9=11ohm

Answer 2

Answer:

a is the right answer 6,3,9, are in series answer