Question

in the hydrocarbon
HC=C-CH3, the state of hybridisation ofcarbon atoms 1,2 and 3 are in the following sequence​

Answer 1

Answer:

CH

3

−CH=CH−CH

3

−C≡CH

We have been asked to find out the hybridization of carbon as 1,3 and 5, just count the no. of sigma (σ)bonds to decide the state of hybridization of the Carbon

1

st

carbon: →2σ bonds and 2πbonds

∴sphybridized

3

rd

carbon: →4σ bonds and no π bonds.

∴sp

3

hybridized

5

th

carbon :→3σ bonds and 1π bond

sp

2

hybridized

∴ the correct answer is option D.−sp (1

st

carbon), sp

3

(3

rd

carbon) and sp

2

(5

th

carbon).