Question

In the hydrogen atom, an electron revolves around a proton in a circular orbit of radius 0.53 A° . Calculate the radial acceleration and the angular velocity of the electron. me = 9.1 x 10⁻³¹ kg, e = 1.6 x 10⁻¹⁹C.

Answer 1

Answer:

0.82×10`−9 N

Explanation:

According to the coulomb's law  opposite charges attract and the like charges repel with the force that is proportional to the product of the charges

Proton in a circular orbit of radius = 0.53 A = 5.3× 10`11 (Given)

e = 1.6 x 10⁻¹⁹C (Given)

The force used is the coulomb attraction force.

Therefore, the force, will be -

F =1/4πε0 ×e²/r²

where e is the charge of an electron

Thus,

F = 9 × 10`9 × (1.6 x 10⁻¹⁹)²C/ (5.3× 10`11)²

= 0.82×10`−9 N