Question

In the hydrogen atom E3-E2=E.Find the ionisation potential in volt.

Answer 1

Explanation:

According to Bohr's atomic theory, the energy of an electron in the stationary states around a nucleus of charge Ze is defined by quantum number n, and is given by,

E (n) = - ( 2 π² m e⁴ Z²/n² h² ) in esu

For hydrogen Z =1, and

E( n ) = - ( 2 π² m e⁴/n² h² )

Substituting for m, e, h, standard values we will get E( n) in ergs. Using 1 eV = 1.6×10^-12 ergs, we will get the energy in eV for various n values as

E ( n ) = - ( 13.6/n² ) eV

The significance of the negative sign is that the electron is bound to the nucleus by Coulomb attractive forces and to remove the electron from the atom, that much energy needs to be supplied.The binding energy of the electron in various orbits,

E (1) = - 13.6 eV when n=1 ( K-shell)

E (2) = - 3.4 eV when n =2 ( L-shell)

E (3) = - 1.5 eV when n = 3 ( M-shell),

and so on.

The ionization energy is the energy to remove the electron from the bound state. In the present case the electron is in an excited state. So depending on the excited state the electron is in, the ionization energy will be 3.4 eV or less.

Answer 2

Explanation:

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