in the in a group of a children child gives a gift to every other child if number of a gift are 132 find the number of children
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Let the number of children be x. Thus, one child will gift others but he will not gift himself. Therefore number of gifts=x-1
Makes sense! Think logically n practically!
Moving on....
No. of gifts=132
Therefore,
132=x (x-1)
132=x^2-x
x^2-x-132=0
Quadratic equation!!!
x^2-12x+11x-132=0
x(x-12) + 11(x-12)=0
(x+11)(x-12)=0
Therefore,
x=-11 or x=12
Since gifts can't be negative
The answer is 12
Makes sense! Think logically n practically!
Moving on....
No. of gifts=132
Therefore,
132=x (x-1)
132=x^2-x
x^2-x-132=0
Quadratic equation!!!
x^2-12x+11x-132=0
x(x-12) + 11(x-12)=0
(x+11)(x-12)=0
Therefore,
x=-11 or x=12
Since gifts can't be negative
The answer is 12
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