Question

in the in the given diagram find the relation between acceleration of blocks M1 and M2. also find the values ​

Answer 1

Answer:

M2 = (M2g-T)/a and M1 = (T-M1g)/a

Explanation:

As we know that,

As we know that,F = ma and W = mg and T = Tension

As we know that,F = ma and W = mg and T = Tensionnow,

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - T

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass => F1 = T - W1

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass => F1 = T - W1=> M1×a = T - M1×g

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass => F1 = T - W1=> M1×a = T - M1×gor, T = M1×a + M1×g. ...(2)

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass => F1 = T - W1=> M1×a = T - M1×gor, T = M1×a + M1×g. ...(2)By equation (1) and (2)

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass => F1 = T - W1=> M1×a = T - M1×gor, T = M1×a + M1×g. ...(2)By equation (1) and (2) we get,

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass => F1 = T - W1=> M1×a = T - M1×gor, T = M1×a + M1×g. ...(2)By equation (1) and (2) we get, M2×g - M2×a = M1×g + M1×a

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass => F1 = T - W1=> M1×a = T - M1×gor, T = M1×a + M1×g. ...(2)By equation (1) and (2) we get, M2×g - M2×a = M1×g + M1×aso, M2(g - a) = M1(g + a)

As we know that,F = ma and W = mg and T = Tensionnow,net force on M2 mass=> F2 = W2-T=> M2×a = M2×g - Tor, T = M2×g -M2×a. ...(1)and, net force on M1 mass => F1 = T - W1=> M1×a = T - M1×gor, T = M1×a + M1×g. ...(2)By equation (1) and (2) we get, M2×g - M2×a = M1×g + M1×aso, M2(g - a) = M1(g + a)or, M1/M2 = (g - a)/(g + a)

Answer 2

Answer:

a1=3a2

Explanation:

May be this will help you..