Question

in the in the given figure triangle ABC and triangle A and B are two right triangle right angled at B and M respectively prove that 1)triangle ABC is congruent to Triangle AMP 2) CA/PA= BC/ MP​

Answer 1

Where is the figure? ??

Answer 2

Answer:

Given, ABC and AMP are two right triangles, right angled at B and M respectively.

(i) In ΔABC and ΔAMP, we have,

∠CAB = ∠MAP (common angles)

∠ABC = ∠AMP = 90° (each 90°)

∴ ΔABC ~ ΔAMP (AA similarity criterion)

(ii) As, ΔABC ~ ΔAMP (AA similarity criterion)

If two triangles are similar then the corresponding sides are always equal,

Hence, CA/PA = BC/MP