In the interval 0 t 1 sec, charge flowing through a conductor is given by q = t2 – 6t + 5. In the given interval, the maximum charge flows in the conductor at time :
Answers
Answered by
0
Answer:
At t=0s max charge flows
Explanation:
The charge flows acc to :
t²-6t+5
At t=0, q= 0-0+5=5 C
at t=1, q= 1-6+5= 0 C
It is clear this is a parabola. All values will lie between 0 and 5 C. So we can safely say max charge flows at t=0s. (Eg at t=0.5, q=2.25C)
Answered by
0
Answer:
At t = 0
it's maximum value becomes 5
At t =1
it's maximum value becomes 0
so it's clear that, at t =0 , it's maximum value is 5
so answer will be 0
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