Question

in the isocles trapezium pqrs ,PR=5x-2cm and QS=8x-7cm.find the length of PR

Answer 1

In an isosceles trapezium, the diagonals are equal
8x-7=5x-2
3x=5
x=5/3
PR=5(5/3) -2
=19/3=6.3cm(approx)
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Answer 2

we know that in isosceles trapezium diagonals are equal 
so    PR = QS

thus 
5x - 2  =  8x-7
so     -3x = -5 
     => x = 5/3
put it in PR 
we get 
PR =      5(5/3) - 2
so PR = 6.33.. cm approx