Math, asked by PravinAmbedkar, 12 days ago

In the isosceles triangle ABC, ∠A and ∠B are equal. ∠ACD is an exterior angle of triangle

ABC. The measures of ∠ACB and ∠ACD are (2y + 10)° and (4y - 16)° respectively. Find

the measures of ∠ACB and ∠ACD. Also find the measures of ∠A and ∠B.​

Answers

Answered by tpld1979
1

Answer:

Angle ACB=72⁰

Angle ACD=108⁰

Angle A=36⁰

Angle B=72⁰

Hope it helps you.

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