Question

In the isosceles triangle ABC in Fig. d, AB = AC. If D and E
are the mid-points of AB and AC, respectively, prove that
CD = BE.​

Answer 1

Answer:

In triangle ABC,

AB=AC(given isosceles)

thus ,DB=EC( AB=AC,MID POINT...SO,HALVES ARE EQUAL)

In triangle DCB  and BEC,

BC=BC(common)

angle BDC=angle CEB

DB=EC(proved)

thus ,triangle DBC and triangle CEB are congruent (SAS)

thus ,DC=EB (CPCT)

Step-by-step explanation: