In the isosceles triangle ABC in Fig. d, AB = AC. If D and E
are the mid-points of AB and AC, respectively, prove that
CD = BE.
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Answer:
In triangle ABC,
AB=AC(given isosceles)
thus ,DB=EC( AB=AC,MID POINT...SO,HALVES ARE EQUAL)
In triangle DCB and BEC,
BC=BC(common)
angle BDC=angle CEB
DB=EC(proved)
thus ,triangle DBC and triangle CEB are congruent (SAS)
thus ,DC=EB (CPCT)
Step-by-step explanation:
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