Question

In the isosceles triangle below, the congruent sides each measure 13 meters. If the base of the triangle is 10 meters, what is the height of the triangle?

Answer 1

Step-by-step explanation:

take the tri. as ABC and the mid point as D,

take tri ADC,

Base BC=10, Then DC=10/2=5 (as mid point divides the tri into 2 equal parts,

Now by Pythagoras theorem,

(AD)2+(DC)2= (AC)2

(AD)2= (AC)2-( DC)2

(AD)2=(13)2+(5)2

=169+25

=root of 194

=