Question

in the isosceles triangle measurement of its equal sides 8cm and the third side is 4cm. Find the cost of the painting at the rate of rupees 5 per centimetre square​

Answer 1

Step-by-step explanation:

Area of an isosceles triangle=

a

b

4a

2

−b

2

Here two equal-sided a=8cm and third side b=4cm.

Here two equal-sided a=8cm and third side b=4cm.∴ Area=

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 4

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8)

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4)

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 =

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 =

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16 =

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16 = 240

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16 = 240

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16 = 240 =4

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16 = 240 =4 15

Here two equal-sided a=8cm and third side b=4cm.∴ Area= 44 4(8) 2 −(4) 2 = 4×64−16 = 256−16 = 240 =4 15

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