In the isosceles triangle pqr angle p and angle Q are equal angle pqr is an exterior angle of triangle pqr the measures of angle prq and angle PRS are (2 x - 30)° and (6 X + 10)° respectively find the measure of angle prq and angle PRS also find the measure of angle p and angle q
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Using the theorem that if the side of a triangle is produced then the interior angle is equal to the sum of two interior opposite angles of the triangle.
Let ΔABC be a triangle where the side BC is produced.
By the theorem we have
∠A+∠B=100
o
…………..(1)
It is given that the interior opposite angles are equal i.e., ∠A=∠B.
∴ Equation (1) becomes
2∠A=100
o
⇒∠A=50
o
⇒∠B=50
o
Using angle sum property of a triangle,
Sum of all angles of a triangle =180
o
⇒∠A+∠B+∠C=180
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⇒100+∠C=180
o
[from (1)]
⇒∠C=180
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−100
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⇒∠C=80
o
.
Hence ∠A=50
o
∠B=50
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∠C=80
o
.
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