In the kite shown, PQ = PR and ∠QPS = ∠RPS
(i) Find the third pair of corresponding parts to make ∆ PQS ≅ ∆PRS by SAS congruence condition.
(ii) Is ∠QSP = ∠RSP?
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Answer:
given PQ=PS QR=QS also PR=PR(common) triangle PQR ... angle QRP= angle PRS(cpct) hence pr bisect angle P and ... Triangle PQR is congruent to Triangle PSR.
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