Question

In the lines XY and MN intersect at O . If angle POY = 90 and a:b= 2:3 find ​

Answer 1

$\huge\tt\colorbox{lime}{Answer ✌️}$

∠POY=90°

∠POX+∠POY=180 °

( supplementary angles )

∠POX+90° =180°

⇒∠POX=90°

a:b=2:3

Let a=2x°

and b=3x°

∠POX=a+b=5x

90 ° =5x

⇒x=18 °

∠MOX=b=3x=54 °

∠MOX+∠NOX=180°

(supplementary angles )

b+c=180 °

54 ° +c=180°

c=180 ° −54° =126°

≻───────⋆✩⋆───────≺

Answer 2

$\LARGE{\underline{\underline{\pink{\sf{Required \: Answer:–}}}}}$

∠POY=90°

∠POX+∠POY=180 °

( supplementary angles )

∠POX+90° =180°

⇒∠POX=90°

a:b=2:3

Let a=2x°

and b=3x°

∠POX=a+b=5x

90 ° =5x

⇒x=18 °

∠MOX=b=3x=54 °

∠MOX+∠NOX=180°

(supplementary angles )

b+c=180 °

54 ° +c=180°

c=180 ° −54° =126°

≻───────⋆✩⋆───────≺