Chemistry, asked by shanishelly33, 4 months ago

In the manufacture of methanol by the reaction of carbon monoxide and hydrogen, some formaldehyde is also formed as a by-product. CO + 2H2 = CH3OH CO + H2 = HCHO A mixture consisting of 20% CO and 80% H2 is allowed to react and the product analyzed 2.92% CO, 19.71% methanol, 6.57% formaldehyde and 70.80% hydrogen. Calculate the following: (a) The percent conversion of limiting reactant (b) The percent excess of any reactant (c) Percent yield of methanol

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Answered by savitakumari60688
0

Answer:

please write it again it is wrong

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