In the middle of a rectangular field measuring 30m x 20m, a well of 7m diameter and 10m depth is dug. The earth so removed is evenly spread over the remaining part of the field. Find the height through which the level of the field is raised. I searched this question and an expert had sent an link similar to this question but i did not get the answer. Please solve and explain.
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Answered by
54
For rectangular field
Lentgh L = 30 m
Breadh B = 20 m
For Well
Radius R = 7/2 m
Height H = 10 m
Thus Volume of sand dug out of the well = pi R^2 * H
= 22/7 * 49/4 * 10
= 385 m^3
Thus Volume of of sand spread over the rest Area = L * B * H
Thus 30 * 20 * H = 385
H = 0.64 m
Thus height of ground will be 0.64 m
Lentgh L = 30 m
Breadh B = 20 m
For Well
Radius R = 7/2 m
Height H = 10 m
Thus Volume of sand dug out of the well = pi R^2 * H
= 22/7 * 49/4 * 10
= 385 m^3
Thus Volume of of sand spread over the rest Area = L * B * H
Thus 30 * 20 * H = 385
H = 0.64 m
Thus height of ground will be 0.64 m
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16
In the middle of a rectangular field measuring 30m x 20m, a well of 7m diameter and 10m depth is dug. The earth so removed is evenly spread over the remaining part of the field. Find the height through which the level of the field is raised. I searched this
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