Chemistry, asked by trickswithme04, 3 days ago

in the mixture of BaSo4 and NH4Cl , which compound is completely volatile?​

Answers

Answered by manishaprajapati2222
0

Answer:

BaCl

2

+(NH

4

)

2

SO

4

→ BaSO

4

+2NH

4

Cl

Above reaction is a double displacement reaction as ions (both cations and anions) of the reacting molecules are exchanged. Barium ion (Ba

2+

) combines with sulphate ion (SO

4

2−

) to form Barium sulphate (BaSO

4

) and ammonium ion (NH

4

+

) combines with chloride ion(Cl

) ion to form ammonium chloride (NH

4

Cl).

The above reaction is also classified as a precipitation reaction because barium and sulphate ions combine to form precipitates of barium sulphate.

Ba

2+

(aq)+SO

4

2−

(aq)→BaSO

4

(s)

Explanation:

whyyyyy

Answered by kaladayatk
0

Explanation:

BaCl

2

+(NH

4

)

2

SO

4

→ BaSO

4

+2NH

4

Cl

Above reaction is a double displacement reaction as ions (both cations and anions) of the reacting molecules are exchanged. Barium ion (Ba

2+

) combines with sulphate ion (SO

4

2−

) to form Barium sulphate (BaSO

4

) and ammonium ion (NH

4

+

) combines with chloride ion(Cl

) ion to form ammonium chloride (NH

4

Cl).

The above reaction is also classified as a precipitation reaction because barium and sulphate ions combine to form precipitates of barium sulphate.

Ba

2+

(aq)+SO

4

2−

(aq)→BaSO

4

(s)

Option D is correct.

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